Abag contains 30 lottery balls numbered 1-30 a ball is selected replaced then another is drawn find each probability p ( and even, then odd ) p ( 7, then a number greater than 16)p ( a multiple of 5, then a prime number ) p ( two even number )

Given : A bag contains 30 lottery balls numbered 1-30 a ball is selected replaced then another is drawn.

To find : Each probability  

1) p ( and even,then odd )  

2) p ( 7, then a number greater than 16)

3) p ( a multiple of 5, then a prime number )  

4) p ( two even number )

Solution :

1) There are 15 even numbers and 15 odd numbers.

Probability of getting even first then odd is

2) Number greater than 16 out of 30 are 14.

Probability of getting 7 first then a number greater than 16 is

3) Multiple of 5 - 5,10,15,20,25,30=6

Prime numbers - 2,3,7,9,11,13,17,19,23,29=10

Probability of getting a multiple of 5, then a prime number  is

4) There are 15 even numbers.

Probability of getting  two even number is

exa:

)

3+11

14

step-by-step explanation:

from this example, we can see that subtracting with integers is the same as adding the opposite. we can solve using a number line or by using the saying "keep, change, change" to us solve. it is important to remember that we can subtract a negative and end up with a larger number than we started with.