Graph 2x plus y is less than 7 and state one point in the solution set

2x + y = 7

First, let's get y alone on one side of the equation so we can solve this more easily:
y = 7 - 2x

You can start to plug-in number to graph your equation. For example, if x = 0, than y = ?. Solve for y:

y = 7 - 2 x 0
y = 7

So if x is 0, than y = 7. Now you can plot your first point on the graph: (0, 7)
Now you do it vice versa, if y = 0, x = ?. So solve for x:

0 = 7 - 2x
0 - 7 = -2x
-7 = -2x
-7/-2 = x
7/2 = x

So when y is 0, x ix 7/2; (7/2, 0)

Just keep plugging in number, for example you can plug in numbers going one digit at a time, which is the easiest way; if x = 1, than y = ?, if x = 2, then y = ? etc.

To "state one point in the solution set", I'm not too sure I know what you mean; perhaps it means that you should show the points that helped you draw the line? I'm sure you will be able to answer it if you have understood what I have said.

I've graphed your equation so you can check your work, it should resemble, to some point, the one have drawn. The two red points I have marked are to show that when x = 0, y = 7. (Remember, your y-intercept should be 7 because we already figured out that when x = 0, y = 7). Don't worry is the slope is not as steep as mine, your slope may, in fact, turn out to be less steep and that does not mean it is wrong.