Mrs. jones buys two toys for her son. the probability that the first toy is defective is 1/3, and the probability that the second toy is defective given that the first toy is defective is 1/5. what is the probability that both toys are defective?

Step-by-step explanation:

Let F denote the event of first  toy is defective and S denote the second toy is defective .

Given: The probability that the first toy is defective

The probability that the second toy is defective given that the first toy is defective  

The formula to calculate the conditional probability is given by :-

Hence, the probability that both toys are defective=

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)