The current size of an image on samuel's computer is shown below: a rectangle is shown. the length of the rectangle is labeled as length equal to 8 inches and the width is labeled as width equal to 10 inches. what are the dimensions of the image at fraction 1 over 2 times its current size

The length and the width of image is  4 inches and 5 inches respectively

Step-by-step explanation:

Given : Length of rectangle is 8 inches

          Width of rectangle is 10 inches

To Find: What are the dimensions of the image at fraction times its current size

Solution:

Length of rectangle is 8 inches

Since we are given that the dimensions of the image at fraction times its current size

So, Length of image =

Thus the length of image is 4 inches.

Width of rectangle is 10 inches

Since we are given that the dimensions of the image at fraction times its current size

So, width of image =

Thus the width of image is 5 inches.

Hence the length and the width of image is  4 inches and 5 inches respectively.

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.