Un automovil de 1,200 kg que viaja a 30 m/s aplica los frenos y derrapa antes de detenerse. Si la fuerza de fricción entre el deslizamiento de las llantas y el pavimento es de 6,000 N, ¿Que distancia recorrerá el coche antes de alcanzar el reposo?

The correct answer is 90 m

Explanation:

According to the scenario, the calculation of the how much far would the car travel prior reaching rest is as follows:

Here the theorem of living forces is applied

-Fd = 1 ÷ 2 m (V^2 - Vo^2)

where,

V = 0

Now the d is

= 1,200km (30 m/s)^2 ÷ (2. 6000)

= 90 m

hence, the calculation of the how much far would the car travel prior reaching rest is 90 m

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