Line j passes through the coordinate points (4, 1) and (-3, -6). What is the y-intercept of the equation that is parallel to line j and passes through point (7, 1)?

The y-intercept (b) of the parallel line is -6.

Explanation:

PART A: First understand that a parallel line will always share the same slope. So let us calculate the slope of line j and whatever that it will be will also be the slope of the parallel line.

slope intercept form: y = mx + b

m = slope

m = y2 - y1 / x2 - x1

m = -6 -1 / -3 - 4

m = -7 /-7

m = 1  (slope of line j and parallel line)

PART B: Now that we have the slope of the parallel line we can substitute the point (7, 1) into it's equation to find it's y-intercept (b).

y = 1x + b

1 = 1(7) + b

1 = 7 + b

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