The flame temperature in an automobile engine is 1699 °f, and the exhaust is emitted at 229 °f. what is the carnot efficiency of the engine?

Solution:

η =  Efficiency ; T(hot) =Temperature of the Hot source ; T(cold) = Temperature of the Cold Sink ;

η = 1 – {T(cold)/T(hot)}

η = 1 – {229 / 1699}

η = 0.6809748595199822 x 100

η = 68.09 %

The answer is 68.09 %,  you can use the Carnot Thermal efficiency Calculator in the Internet.

so the story tells of someone named kaushik choudhuri, but he does not narrate the story, a girl named hema does. hema tells the story in a second person point of view because you (the reader) are supposed to be the boy named kaushik.

here's an excerpt i found: "i was ushered into the fitting room, your mother watching approvingly as i took off my coat and sweater and tried on the bra."

source:

macon. i believe thats the answer

sorry if im wrong.