The dipole moment of hbr is 0.80d. what is the dipole moment of hbr in c⋅m?

The correct answer for this question is this one: "2.7×10^-30 C·m "
We have  + H -- Br - 

The percent ionic character of the HBr bond is about 13% 
Percent ionic char = 100(1 - e^(-ΔEN²/4)) 

1D = 3.33564×10^-30 C·m 
0.80D = 2.7×10^-30 C·m 

We have to take note to use two significant digits.

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The correct answer is b