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History, 09.10.2019 16:20 nunu5671

An equivalent equation has been written by multiplying the second equation by 2. 4x – 9y = 7 β†’ 4x – 9y = 7 2(–2x + 3y = 4) β†’ –4x + 6y = 8 what is the solution to the system? ((negative startfraction 19 over 2 endfraction, negative 5), –5) (–5, (negative 5, negative startfraction 19 over 2 endfraction)) ((negative startfraction 15 over 2 endfraction, negative startfraction 11 over 3 endfraction), ) ((negative startfraction 19 over 10 endfraction, startfraction 1 over 15 endfraction), )

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An equivalent equation has been written by multiplying the second equation by 2. 4x – 9y = 7 β†’ 4x –...
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