Solve,3²*+¹=4(³*)+1=0​

3

2

x

x

3

1

−

28

(

3

x

3

1

)

+

1

=

0

Let

u

=

3

x

Now

3

u

2

−

28

(

u

3

)

+

1

=

0

3

u

2

−

28

u

3

+

1

=

0

9

u

2

−

28

u

+

3

=

0

Using the quadratic equation

u

1

,

2

=

−

b

±

√

b

2

–

4

a

c

2

a

you get

u

=

28

±

√

28

2

−

4

×

9

×

3

2

×

9

u

=

28

±

√

784

−

108

18

u

=

28

±

√

676

18

u

=

28

±

26

18

u

=

54

18

or

u

=

2

18

u

=

3

or

u

=

1

9

Put

3

x

back in for

u

to get

3

x

=

3

or

3

x

=

1

9

3

x

=

3

1

or

3

x

=

3

−

2

Therefore,

x

=

1

or

x

=

−

2

Explanation:

1. h

2.a

3. i

4. d

5. b

6.f

7.g

8.e

9.c

i hope that this is

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