If 3 grams of active ingredient are needed to make 1 pint of a suspension, how much active ingredient is needed to make 1 gallon of the suspension?

25mL of active ingredient is needed to make 1 gallon of the suspension

Explanation:

3 grams of active ingredient are needed to make 1 pint (16 ounces = 16×28.35 grams = 453.6 grams) of the suspension

Volume active ingredient needed to make 1 gallon (3.7854L = 3.7854×1000mL = 3785.4mL) = 3785.4mL × 3g/453.6g = 25mL

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