Adentist’s drill starts from rest. after 1.28 sof constant angular acceleration it turns at a rate of 24040 rev/min

This question is an incomplete question, here is a complete question.

A dentist’s drill starts from rest. After 1.28 s of constant angular acceleration it turns at a rate of 24040 rev/min. Find the drill's angular acceleration in rad/s²

Answer : The angular acceleration of the drill is,

Explanation :

Formula used for angular acceleration of the drill is:

where,

a = angular acceleration

= initial angular velocity = 0

= final angular velocity =

t = time = 1.28 s

Now put all the given values in the above formula, we get:

Therefore, the angular acceleration of the drill is,

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