Find the area of a triangle whose base is 2√3 in. and height is 3√3 in. type a numerical answer in the space provided. can you show me the work i need to understand how? i'm

9 (in square units)

WORKINGS

Base of Triangle, b = 2√3

Height of Triangle, h = 3√3

Formula for Area of Triangle, A = (b * h)/2

Area of the Triangle = (2√3 * 3√3)/2

= (2 * √3 * 3 * √3)/2

Collect like terms in the bracket

= (2 * 3 * √3 * √3)/2

= [(2 * 3) * (√3 * √3)]/2

= (6 * 3)/2

= 18/2

= 9 (In square units)

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