Aline has equation y=x−5. the line is shifted 3 units to the left and 1 unit up. which points are on the graph of the line after these 2 transformations are applied?

First, we need to apply the transformations to the equation. To represent a transformation 3 units left, you add 3 to 'x' to shift the line. Next, you add 1 to the whole equation to shift the whole line up. Then, plug in values for 'x' to get some 'y' values.

y = x - 5
y = (x + 3) - 5
y = (x + 3) - 4

y = (1 + 3 ) - 4
y = (4) - 4
y = 0
(1,0)

And so on. Hope this helps!

The name may be in importnce  to them