What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point (4.1)? (-3, 3) 2 Oy-1=-2(x - 4) Oy-1=-{(x-4) Oy-1 = {(x - 4) Sy Oy - 1 = 2(x - 4)​

A. y - 1 = -2(x - 4)

Explanation:

Recall that parallel lines have the same slope value.

Thus, the first step is to find the slope of the line given.

✔️Slope of the line that runs through (-3, 3) and (-2, 1):

slope (m) = change in y/change in x

Slope (m) = (1 - 3)/(-2 -(-3)) = -2/1

Slope (m) = -2

The slope (m) of the line that is parallel to the given line would also be -2.

✔️The slope of the line that is parallel to the given line which goes through the point (4, 1) can be written in point-slope form, y - b = m(x - a). Where,

(a, b) = (4, 1)

m = -2

Substitute the values into the equation

The equation of the parallel line would be:

y - 1 = -2(x - 4)