A stone dropped freely from 72m height of the tower and reaches the "ground on 6 seconds
calculate acceleration due to gravity of that stone
At what condition does the acceleration due to
gravity becomes Zero​

Explanation:

At what condition does the acceleration due to  gravity becomes Zero​=at bottom

h=72

g=10

t=6

SOLUTION= h=at+1/2gt2   (2 is the square)

72=a*6+1/2*10*36

72=a*6+1/2*360

72=a*6+180

72=a*186

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