For every 3.3 km a rock is buried, the pressure placed upon it increases 0.1 gigapascal (100 million pascals). If rock undergoing metamorphosis is buried at 16 km, what is the pressure placed on that rock? (Hint: The pressure of Earth's surface is .101 gigapascal.)

Explanation:

Given

Required:

Determine its pressure at 16km

Let the pressure at 16km be x.

So, the rate at 16km is:

Equate both rates

Multiply both sides by 16

the answer would be the third option, "no, ariel should have added 9^2 and 12^2 and compared that to 15^2."

this is found through the pythagorean theorem, which is a^2 + b^2 = c^2.

this is the correct way of solving the problem:

9^2 + 12^2 = 15^2

81 + 144 = 225

225 = 225