3. an undisturbed soil sample has the following data (source - lu & evett): 1. void ratio = 0.78 2. water content -12% 3. specific gravity of solids - 2.68 determine: 1. wet unit weight (in g/ce) 2. dry unit weight (in g/ce) 3. degree of saturation 4. porosity

Wet unit weight = 1.94 g/cc

Dry unit weight =1.05 g/cc

density of saturation = 0.41

porosity = 0.43

Explanation:

given data

Void ratio = 0.78

Water content -12%

Specific gravity of solids - 2.68

to find out

Wet unit weight and Dry unit weight and Degree of saturation and Porosity

solution

we know that Wet unit weight formula is

Wet unit weight = density of water

here Gs is specific gravity of soild and e is void ratio and density of water is 1

so Wet unit weight =

Wet unit weight = 1.94 g/cc

and

Dry unit weight = density of water

Dry unit weight =

Dry unit weight =1.05 g/cc

and

density of saturation is

density of saturation = Wc ×

her Wc is water content

so density of saturation = 0.12 ×

density of saturation = 0.41

and

porosity is

porosity =  

porosity =    

porosity = 0.43

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