In this section, we will continue with the samples we used to determine bd and tps. this time you need to determine om, ov, water depth, and paw. assume your soils were collected at fc below is the sample information you need sample 1: cylinder 1.5 cm in diameter. 5 cm in height. most weight 13.46 д. dry weight 10.25 g, ompwp 0.13g h2o/g soil sample 2: 7" cube, moist weight 18.2 ibs, dry weight 14.8 lbs, ompwp 0.17g h2o/g soil

Round it to the nearest tenth

May consider a group  g=({0,1},+)g=({0,1},+)where  ++  will work as the xor operator like we work in boolean algebra. note here, that ‘00’ and ‘11’ are not the usual 0 and 1 that we work with everyday. the elements are  called  ‘00’ and ‘11’ and  may not mean  zero (nothing) and one (single). ‘00’ is the identity for the given binary operator +, meaning that any element operated with ‘00’ gets us that element itself.  for a set  ss  in  g′g′  having more elements than just  {0,1}{0,1}  the values for  a+b∈sa+b∈s, such that  a∈s,b∈sa∈s,b∈s, have to be first defined, only then can you determine the value of  1+11+1. the answer could possibly have been  22  if oanswer is25,000

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