Identify the third term in the expansion of (7x – 2y)^3

The solution to the problem is as follows:

The third row of Pascal's triange = 1 ... 3 ... 3 ... 1 

(7x - 2y)^3 = 

1(7x)^3 + 3(7x)^2 ( (-2y)^1 )+ 3(7x)^2 ( (-2y)^2 ) + 1( (-2y)^3 ) 

= 343 x^3 + 588 x^2 y^2 - 294 x^2 y - 8y^3


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