A bullet weighing 0.08 lb is fired with a horizontal velocity of 1800 ft/s into the lower end of a slender 23-lb bar of length L = 30 in. Knowing that h = 12 in. and that the bar is initially at rest. Determine the angular velocity of the bar immediately after the bullet becomes embedded.

hello attached below is the missing image the slender weight is different from what is in the question here so I worked with 23-Ib as requested in the question

answer

≈ 12.17 Rad/sec

Explanation:

weight of bullet ( Wb ) = 0.08 Ib

horizontal velocity = 1800  ft/s

Slender(Wr) = 23-Ib bar with

length ( L ) = 30

h = 12 inches

Vro = 0

Calculate the angular velocity of the bar immediately after the bullet becomes embedded  

attached below is a detailed solution

6.708 = ( 0.05011 + 0.5011 ) w'

w' = 6.708 / 0.55121 ≈ 12.17 Rad/sec