A steel rod of circular cross section will be used to carry an axial load of 89 kips. The maximum stresses in the rod must be limited to 31 ksi in tension and 14 ksi in shear. Determine the required diameter for the rod.

d = 1.9 in

Explanation:

Since, the tension force is greater than the shear force. Hence, the area of cross-section shall be limited by the tension:

Tension = Force/Area

Area = Force/Tension

Area = 89 kips/31 ksi

Area = 2.87 in²

but,

Area = πd²/4

2.87 in² = πd²/4

(2.87 in²)(4)/π = d²

d = √(3.65 in²)

d = 1.9 in

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