A cyclist is turning the pedals of his bicycle at a speed of 60RPM while exerting a torque of 1 lb-ft. If the driven wheel is rotating at 240 RPM What torque is exerted on the back wheel?

c. multiplying the difference in the two torques by the time for which the new torque is applied

Explanation:

For a particle moving in a circular orbit, the angular momentum is

L = r x p = m r2 ω.

For a continuous mass distribution, L = ∫ dm r2 ω = Iω

Angular momentum is a vector that is parallel to the angular velocity.

If there is no net torque acting on a system, the system's angular momentum is conserved.

A net torque produces a change in angular momentum that is equal to the torque multiplied by the time interval over which the torque is applied. From Newton's second law for rotational motion,

ΔL = Δt*τ

In differential form,

Στ = dLdt = d(Iω)dt = Idωdt+ ω

Integrating the general equation gives: ∫ ∑ τ dt = ΔL

The net torque equals the rate of change of the angular momentum.

The net torque acting over a time interval is the angular impulse.

Explanation:

answer:

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