The current through a 10-mH inductor is 10e−t∕2 A. Find the voltage and the power at t = 8 s.

The voltage is - 0.9158 mV

The power is - 0.1677 mW

Explanation:

Given;

current through the inductor, i(t)  = -----equation (1)

inductance, L = 10 mH

given time, t  = 8 s

The voltage across the inductor is given by;

when t = 8 s, the voltage will be ;

Power is given by;

P = I V

When t = 8, the current "I" is given by;

P = 0.1832 x (-9.158 x 10⁻⁴)

P = -1.677 x 10⁻⁴ W

P = -0.1677 mW

answer:

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explanation:

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2. determine the proper pump operating conditions and bit nozzle sizes for - chegg