Wind blows on the side of a fully enclosed hospital located on open flat terrain where V= 120 mi/h. Determine the external pressure acting on the leeward wall, if the length and width of the building are 200 ft and the height is 30 ft. Take Ke 1.0.

The external pressure is p = -21.9 psf or p = -8.85 psf

Explanation:

Given :

Velocity of wind, v = 120 mi / hr

  (wind direction factor)

 = topographical factor (for flat terrain)

= velocity pressure at height h

But for height h = 30 ft, = 0.98 (from table)

        = 36.16

Now, ,   so (from table)

where, p = external pressure

            G = 0.85 = gust factor (for typical rigid building)

              (internal pressure co efficient)

Therefore putting the values,

p = -21.9 psf or p = -8.85 psf

unlike the threaded fasteners which are used to clamp the machine members, power screws are used to transmit power. common applications of power screws are: screw jacks: to lift weight. lead screw of lathe: for axial movement of tool and its precise positioning.

i mean i gues

explanation: