For flow over a flat plate with an extremely rough surface, convection heat transfer effects are known to be correlated by the Nμ x= 0.04 Rex^0.9 Pr^1/3

For airflow (v =15.89x10^-6m² /s, Pr=0.71 and density 1.16kg/m^3) at 50 m/s, what is the surface shear stress at x =1m from the leading edge of the plate?

the surface shear stress at x =1m from the leading edge of the plate is 4.1973 N/m²

Explanation:

Given that;

density s = 1.16 kg/m³

velocity = u = 50 m/s

kinetic viscosity r = 15.89 × 10⁻⁶ m²/s

xL = 1m from the leading edge of the plate

Now Reynold number (Rex)

Rex = UxL / r

Rex = (50 m/s × 1m ) / 15.89 × 10⁻⁶ m²/s

Rex = 3146633.1025

since Rex is greater than 5×10⁵ { Turbulent flow }

so Local skin friction coefficient

⇒ Cfx = 0.0577 / (Rex)^1/5

Cfx = 0.0577 / (3146633.1025)^1/5

Cfx = 0.0028947

Now Shear stress (y)

y = Cfx × 1/2 × su²

y = 0.0028947 × 1/2 × 1.16 × (50)²

y = 4.1973 N/m²

∴ the surface shear stress at x =1m from the leading edge of the plate is 4.1973 N/m²

answer:

the answer is d

explanation:

angvrswer:

vfg

grfhrtrhr:

j

h

j

jjj

jj

j

j

j

m

j

h

yjujuju

jujuhuyhyt

j

hy

h

gh

g

g

g

g

gg

t

gt

gt

g

g

g

g

g

ef

f

d

dd

d

d

dd

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

d

f

s

bv

fb

c

fd

f

bf

bgf

n

g

bgr

gbr

bgr

gtr

bgr

gb

gb

gbgbbg

b

bgg

bbg

bfg

s

dcwf

fdb

b

ggb

bg

b

d

fh

d

e

f

w

fh

cd

cr

r

h

f

ww

a

v

f

vf

tr

rfe

rr

g

gg

e

go

d

d

c

r

rv

ng

gtg

gegte

g

gf

gf

g

gff

gf

gf

g

g

g

f

ds

wd

dfg

h

gfdsax

cvfbgnh

jmhngf

dsaazxscvb

nmhgb

fvdcsxaz

zxcv

bghn

fd

gb

h