You wish to assess, approximately, the thermal conductivity λ of polyethylene (PE). To do so you block one end of a PE pipe with a wall thickness of x = 3 mm and diameter of 30 mm and fill it with boiling water while clutching the outside with your other hand. You note that the outer surface of the pipe first becomes appreciably hot at a time t ≈ 18 seconds after filling the inside with water. Use this information, plus data for specific heat C p and density rho of PE, to estimate λ for PE. How does your result compare with the listed value in the CES EduPack?

Complete Question

The complete question is shown on the first uploaded image

The  value is

The calculated value is greater than the value from the CES EduPack

(A picture of the listings of the CES EduPack is shown on the second uploaded image  )

Explanation:

From the question we are told that

     The distance x that the heat diffuses in the time t is approximately

Where

Now from the question we know that t =  18 s  and  x =  3mm  = 0.003 m,

So  

=>  

=>    

Generally the density of the polyethylene is  

So

=>    

From the CES EduPack the value  listed for thermal conductivity λ of polyethylene is

So the calculated value is greater that the value from the CES EduPack

the warning light flashes for a second or two when the engine starts. if it stays on, there's must be something wrong with the coolant. you should never dare to continue driving when the light is on. pull over as soon as possible and shut the engine off.

hope this is what you're talking about

answer:

a

explanation: