A rectangular steel bar 37.5 mm wide and 50 mm thick is pinned at each end and subjected to axial compression. The bar has a length of 1.75 m. The modulus of elasticity is 200 Gpa. What is the critical buckling load

The critical buckling load is

Explanation:

Given that:

the width of the rectangular steel = 37.5 mm = 0.0375 m

the thickness = 50 mm  = 0.05 m

the length = 1.75 m

modulus of elasticity = 200 Gpa = 200 10⁹ × Mpa

We are to calculate the critical buckling load  

Using the formula:

where;

The critical buckling load is

b. check your rearview mirror

explanation: