If the resistance reading on a DMM'S meter face is to 22.5 ohms in the range selector switch is set to R X 100 range, what is the actual measure resistance of the circuit?

The answer is 2.25 kΩ

Explanation:

Solution

Given that:

The resistance reading on a DMM'S meter face = 22.5 ohms

The range selector switch = R * 100 range,

We now have to find the actual measure resistance of the circuit which is given below:

The actual measured resistance of the circuit is=R * 100

= 22.5 * 100

=2.25 kΩ

Hence the measured resistance of the circuit is 2.25 kΩ

answer:

clock

explanation:

always running (on) sing each hour (chime) and the clock face (front)