An aluminium bar 600mm long with diameter 40mm has a hole drilled in the centre of the bar. The hole is 30mm in diameter and is 100mm long. If the modulus of elasticity for the aluminium is 85GN/m^2 Calculate the total contraction on the bar due to a compressive load of 180kn

The total contraction of the bar is 1.228 mm

Explanation:

The parameters given are;

Length of aluminium bar = 600 mm

Diameter of aluminium bar = 40 mm

Diameter of hole in aluminium bar = 30 mm

Length of hole = 100 mm

Modulus of elasticity of aluminium = 85 GN/m²

Applied compressive load = 180 kN

Where:

δ = Total contraction of the bar

A₁ for the hole section =

A₂ for the solid section =

L₁ = 100 mm

L₂ = 600 - 100 = 500 mm

The total contraction of the bar = 1.228 mm.