The gas-phase reaction between methanol (A) and acetic acid (B) to form methyl acetate (C) and water (D)CH3OH + CH3COOH ⇌ CH3OOCCH3 + H2Otakes place in a batch reactor and proceeds to equilibrium. When the reactor mixture comes to equilibrium, the mole fractions of the four reactive species are related by a reaction equilibrium constant yC⁢ yD yA yB⁢ = Keq⁢ =6.87The feed to the reactor consists of nA0, nB0, nC0, nD0 and nI0 gram moles of A, B, C, D and an inert gas I respectively. a. If nA0 = 0.800 nB0, and all other input quantities are 0.0, what is the equilibrium fractional conversion of A? Entry field with correct answerb. It is desired to produce 60.0 moles of methyl acetate starting with 65.0 moles of methanol, an unknown amount of acetic acid, and no other components. If the reaction proceeds to equilibrium, how much acetic acid must be fed?Required acetic acid: Entry field with correct answer molWhat is the composition of the final product?yacetic acid: Entry field with incorrect answerymethylacetate: Entry field with incorrect answerymethanol: Entry field with incorrect answerywater:c. Suppose it were important to reduce the concentration of methanol by making its conversion at equilibrium 99.0%. Again, assuming the feed to the reactor contains only methanol and acetic acid and that it is desired to produce 60.0 moles of methyl acetate, determine the extent of reaction and moles of methanol and acetic acid that must be fed to the reactor.