A fluid of specific gravity 0.96 flows steadily in a long, vertical 0.71-in.-diameter pipe with an average velocity of 0.90 ft/s. If the pressure is constant throughout the fluid, (a) what is the viscosity of the fluid

0.00650 Ib s /ft^2

Explanation:

diameter ( D ) = 0.71 inches = 0.0591 ft

velocity = 0.90 ft/s ( V )

fluid specific gravity = 0.96 (62.4 )  ( x )

change in pressure ( P ) = 0 because pressure was constant

viscosity =  (change in p - X sin∅ ) / 32 V

              = ( 0 - 0.96( 62.4) sin -90 ) * 0.0591 ^2  / 32 * 0.90

              = - 59.904 sin (-90) * 0.0035 / 28.8

              = 0.1874 / 28.8

  viscosity = 0.00650 Ib s /ft^2

The fluid viscosity is 0.00650 Ib s /ft^2

Explanation

From the given question, let recall the following:

A fluid of specific gravity is given as = 0.96

The average velocity is = 0.90. ft/s

The diameter pipe = 0.71

Then

The diameter ( D ) = 0.71 inches  which now becomes = 0.0591 ft

The expression is defined as:

The fluid specific gravity * the change in pressure

0.96 (62.4) * (P) = 0

The pressure here must remain constant

Viscosity is defined as:

viscosity =  (change in p - X sin∅ )  / 32 V

Which is

             = ( 0 - 0.96( 62.4) sin -90 ) * 0.0591∧² / 32 * 0.90

              = - 59.904 sin (-90) * 0.0035 / 28.8

               = 0.187 4 / 28.8

Therefore,

The viscosity of the fluid is

viscosity = 0.00650 Ib s /ft∧²

import math

x=int(input("enter a number: "))

print (math.sqrt(math.fabs(