Part A A thin-walled cylindrical pressure vessel is subjected to an internal gauge pressure, p=75 psi. It had a wall thickness of 0.25 inches and an inner diameter of 8 inches. Use Mohr’s Circle to determine the absolute maximum shear stress in the pressure vessel when it is subjected to this pressure. A thin-walled cylindrical pressure vessel is subjected to an internal gauge pressure, . It had a wall thickness of 0.25 inches and an inner diameter of 8 inches. Use Mohr’s Circle to determine the absolute maximum shear stress in the pressure vessel when it is subjected to this pressure. 1200 psi 900 psi 600 psi 300 psi

600 psi

Explanation:

Hoop stress is the circumferential force per unit areas (Psi) in the pipe wall due to internal pressure. It can be regarded to as the largest tensile stress in a supported pipe carrying a fluid under pressure. Trenchless methods are used to replace pipes that have failed or correct system issues such as clogs or blockages that inhibits internal flow.

Firstly, calculate the hoop stress in the pressure vessel which is given as:

σh= pd/2t

Where,

Internal pressure gauge(P) = 75psi

Inner diameter(d) = 8inches

Wall thickness = 0.25 inches

With the above, σh is given as:

σh= 75 × 8/ 2× 0.25

σh= 600/0.5

σh=1200 psi

Next, the longitudinal stress in the pressure is calculated. This is given as:

σi= pd/4t

σi= 75 x 8/4 ×0.25

σi= 600psi/1

σi= 600psi

The maximum shear stress is the maximum concentrated shear force in a small area.

It is very critical for structural engineers to locate and evaluate the maximum shear stress in a member in order to design.

After this, the Mohr circle is used to calculate the average maximum stress in the pressure vessel which is given as follows:

Tmax=σh/2

Tmax= 1200/2

Tmax= 600psi.

In conclusion, the maximum shear stress in the pressure vessel is 600psi

rmax = 600psi

Explanation:

Hoop stress=pd/2t=75x8/2×0.25=1200psi

Now the longitudinal stress =pd/4t=75x8/4x0.25=600psi

Now the absolute max. Shear stress =1200/2 =600psi