A trapezoidal ditch is designed with a bottom width of 3 space f t and side slopes of m equals 1 on both sides. The channel is made of concrete (n equals 0.013) and has a longitudinal slope of 1 percent sign. If the flow rate on a particular day is 125 space f t cubed divided by s, determine the depth of flow in the channel. Assume steady uniform flow.

d = 3.25 ft

Explanation:

n = 0.013

side slope, m = 1

Flow rate, Q = 125 ft³/s

Width, w = 3 ft

Longitudinal slope, S = 1% = 0.01

Let the depth = d

Area, A = wd = 3d

The equation for the flow rate can be given as:

...........................(1)

Substituting all appropriate values into equation (1)

On solving the equation above

d = 3.25 ft

answer:

Explanation:

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answer:

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