Based on the average number of moles of IO3- in your samples, and the initial volume of those samples, what is the solubility of Ca(IO3)2 in mol/L of the saturated solution in 0.01 M KIO3?

Answer : The solubility of is, 0.0036 M

Explanation :

First we have to calculate the concentration of

Now we will subtract  that came from

Concentration of = 0.0172 - 0.01 = 0.0072 M

Now we have to calculate the solubility of

                     s           2s

= 0.0072 M

2s = 0.0072 M

s = 0.0036 M

Thus, the solubility of is, 0.0036 M