Steam enters an adiabatic nozzle at 2.5 MPa and 450oC with a velocity of 55 m/s and exits at 1 MPa and 390 m/s. If the nozzle has an inlet area of 6 cm2 , determine (a) the exit temperature. (b) the rate of entropy generation for this process.

(a). The value of temperature at turbine exit = 687.64 K

(b). The rate of entropy generation for this process =   = 0.3157

Explanation:

Pressure at inlet = 2.5 M pa

Temperature = 450 °c = 723 K

Velocity at inlet = 55

Pressure at exit = 1 M pa

Velocity at exit = 390

Value of specific heat for steam = 2.108

(a). Apply steady flow energy equation for adiabatic nozzle

⇒ + = +  ----------- ( 1 )

⇒ - = -

⇒ ( - ) =   -

⇒ 2.108 ( - 723 ) = -

⇒ 2.108 ( - 723 ) = - 74.53

⇒ ( - 723 ) = - 35.36

⇒ = 687.64 K

This is the value of temperature at turbine exit.

(b). Rate of entropy generation for this process is given by

= - R

Put all the values in above equation we get

⇒ = 2.108 - 0.46

⇒ = - 0.1057 + 0.4214

⇒ = 0.3157

This is the value of entropy generation for this process.

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answer:

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