A process temperature is known to fluctuate with a frequency of 0.1 Hz. The engineer needs to monitor this process using a first-order thermocouple and wishes to have no more than 2% amplitude reduction.

a. What time constant of the thermocouple is needed?

t ≤ 0.31s

Explanation:

Given

Frequency = 0.1Hz

Dynamic Error:

σ = 1 - M(σ)

From the question

σ= 1 - M(σ) ≤ 2%

1 - M(σ) ≤ 0.02

The above corresponds to

M(σ) = 1/(1 + (wt))² ≥ 100% - 0.02

M(σ) = 1/(1 + (wt))² ≥ 1 - 0.02

M(σ) = 1/(1 + (wt))² ≥ 0.98

Since frequency = 0.1Hz

w = 2πf =

w = 0.628571428571428

w = 0.628rads

So, M(0.628) = 1/(1 + (0.628t)²) ≥ 0.98

Solving 1/(1 + (0.628t)²) ≥ 0.98 we get that

t ≤ 0.31s

the correct answer is c.stops after infancy and childhood.

myelin is the substance of the central nervous system (cns) that insulates nerve cell axons to increase the speed at which nerve impulse travels. myelination is a process of myelin formation. this process occurs postnatally, begins in the embryo during the midst of early development and finishes after birth.

answer:

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explanation: