The design specifications of a 1.2-m-long solid transmission shaft require that the angle of twist of the shaft not exceed 48 when a torque of 750 N?m is applied. Determine the required diameter of the shaft, knowing that the shaft is made of a steel with an allowable shearing stress of 90 MPa and a modulus of rigidity of 77.2 GPa

c = 18.0569 mm  

Explanation:

We will find required diameter based on angle of twist and based on shearing stress. The larger value will govern.  

Given that,

Applied Torque,T = 750 N.m

Length of shaft, L = 1.2 m

Modulus of Rigidity,G = 77.2 GPa

Allowable Stress, г = 90 MPa

Maximum Angle of twist  

∅ = 4°

∅ = 4π/180

∅ = 69.813 *10⁻³ rad

Required Diameter based on angle of twist  

∅=TL/GJ

∅ =

∅ =  

∅

c = 18.0869 *10⁻³ rad

Required Diameter based on shearing stress

г = T/J*c

г = [T/(J*/2*c⁴)]*c

г =[2T/(J**c^⁴)]*c

c = 17.441*10^-3 rad

Minimum Radius Required  

We will use larger of the two values  

c= 18.0569 x 10⁻³ m  

c = 18.0569 mm  

the clapeyron equation (also called the clausius-clapeyron equation) relates the slope of a reaction line on a phase diagram to fundamental thermodynamic properties.

explanation:

answer:

yes that is right have a good day