Consider an InSb NW with ballistic mean free path of 150nm. Calculate the current through a 250nm long InSb NW when a 100mV bias is applied. Assume that valley degeneracy 1.

Explanation:

Given parameters include:

V = 100mV = 100 × 10⁻³ V

mean free path(W) = 150nm = 150 × 10⁻⁹ m

Length = 250 nm

From Ohm's Law ;

V = IR

   ---------- equation (1)

Also;

where:

= resistivity  of InSb = 4 × 10⁻¹³ Ω-m

L = length

A = area of cross section

Replacing our values in the above equation; we have:

Ω

Ω

From equation (1):

Therefore;

Ω

Since 1 V/Ω = 0.001 kilo ampere (KA)

Then;

energy can cross the boundaries of a closed system in the form of heat and mass

explanation:

answer:

an example of solubility is salt or sugar dissolving in water.

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