) An electrical heater 100 mm long and 5 mm in diameter is inserted into a hole drilled normal to the surface of a large block of material having a thermal conductivity of 5 W/m·K. Estimate the temperature reached by the heater when dissipating 50 W with the surface of the block at a temperature of 25°C.

Th = 40.91 C

Explanation:

We must use the equation for heat current in conduction

                         Where k is the thermal conductivity of the material

                                     A is the cross-sectional area

                                     (Th -Tc) is the temperature difference

                                  and L is the length of the material

Thus

Isolating Th, we have

Th = 40.91 C

i mean i gues

explanation:

answer:

a

explanation: