At what voltage would a () capacitor have the minimum energy to raise by ignoring all losses in the system? If needed, you may assume a gravitational acceleration of 9.80 m/s2.

V = 280.15 V

Explanation:

" The complete question is attached with figure"

Given:

- The capacitance of the capacitor C = 10 nF

- The amount of mass attached to motor m = 4 grams

- The amount of distance it is to be lifted h = 1 cm

- Ignore all other losses in the system

Find:

- The voltage required to lift the mass m through distance h?

Solution:

- The conservation of energy for the entire system is written as:

                            Work_gravity = U_c

Where,

           Work_gravity: Work done by gravity on mass m

           U_c: The amount of energy stored in a capacitor

                             m*g*h = 0.5*C*V^2

                             V^2 = 2*m*g*h / C

                             V = sqrt ( 2*m*g*h / C )

Plug in the values:

                             V = sqrt ( 2*0.004*9.81*0.01 / 10*10^-9 )

                             V = sqrt ( 78,480)

                             V = 28.15 V

answer:

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