Liquid toluene is flowing through a pipe at a rate of 175 m 3 / h 175m3/h . what is the mass flow rate of this stream in kg/min? what is the molar flow rate in mol/s? in fact, the answer to part (a) is only an approximation that is almost certain to be slightly in error. what did you have to assume to obtain the answer?

(a) Mass flow rate is 2528.75 kg/min

(b) Molar flow rate is 458.1 mol/s

(c) Toulene is in-compressible at standard temperature and pressure

Explanation:

The volume flow rate of liquid toulene is given:

Volume Flow Rate = 175 m^3/h

Density of Liquid Toulene = 867 kg/m^3

Molar mass of Toulene = 92 g/mol = 0.092 kg/mol)

(a)

Thus, the mass flow rate of toulene will be:

Mass Flow Rate = (Volume Flow Rate)(Density)

Mass Flow Rate = (175 m^3/h)(867 kg/m^3)

Mass Flow Rate = (151725 kg/h)(1 h/60 min)

Mass Flow Rate = 2528.75 kg/min

(b)

Now, for molar flow rate we use formula:

Molar Flow Rate = (Mass Flow Rate)/(Molar Mass)

Molar Flow Rate = (2528.75 kg/min)/(0.092 kg/mol)

Molar Flow Rate = (27486.41 mol/min)(1 min/60sec)

Molar Flow Rate = 458.1 mol/s

(b)

The assumption is that Toulene is in-compressible at standard temperature and pressure. So, that its density can be taken constant.

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