Ihave embedded this numerical approximation into a function. go to the r code "fillrateapproximation_part_i. r". except, oopsies, i’ve made a bunch of mistakes. i’ve also left out some parts of the formula that you need to go to the above pdf to obtain. your task is to fix all the typos and errors, and fill in the missing information. make it so that when we select all and run the entire set of code (including the rm(list = line), it prints back the q level for demand mean = 800, standard deviation = 200, and fill rate = 0.98.

Acommercial grade cubical freezer, 4 m on a side, has a composite wall consisting of an exterior sheet of 5.0-mm thick plain carbon steel (kst= 60.5 w/m k), an intermediate layer of 100-mm thick polyurethane insulation (kins 0.02 w/m k), and an inner sheet of 5.0- mm thick aluminium alloy (kal polyurethane insulation and both metallic sheets are each characterized by a thermal contact resistance of r 2.5 x 104 m2 k/w. (a) what is the steady-state cooling load that must be maintained by the refrigerator under conditions for which the outer and inner surface temperatures are 25°c and -5°c, respectively? (b) for power saving purpose, which wall material should be increased/reduced in. thickness in order to reduce 50% of the cooling load found in part (a)? redesign the thickness of the proposed material. 177 w/m-k). adhesive interfaces between the q=575.93 w