Write a loop that sets each array element to the sum of itself and the next element, except for the last element which stays the same. be careful not to index beyond the last element. ex: initial scores: 10, 20, 30, 40scores after the loop: 30, 50, 70, 40the first element is 30 or 10 + 20, the second element is 50 or 20 + 30, and the third element is 70 or 30 + 40. the last element remains the same. sample output: #include int main(void) {const int scores_size = 4; int bonusscores[scores_size]; int i = 0; bonusscores[0] = 10; bonusscores[1] = 20; bonusscores[2] = 30; bonusscores[3] = 40; /* your solution goes here */for (i = 0; i < scores_size; ++i) {printf("%d ", bonusscores[i]); }printf("\n"); return 0; }

answer:

not me

explanation:

answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

//main function

int main()

{

  // variable

 int n;

 cout<<"enter a number:";

 // read the input

 cin>>n;

 // find the square root of the absolute value

 float square_root=sqrt(abs(n));

 // print the square_root

 cout<<"square root of "<<n<<" is: "<<square_root<<endl;

  return 0;

}

Explanation:

Read a number from user and assign it to "n".Then find its absolute value with abs() function.Then calculate the square root of the absolute value with sqrt() function.Print the square root of the number.

Output:

enter a number:-17

square root of -17 is: 4.12311

                                                         This is easy

                                                     sinserly Natalie 7 grader (this is not that hard)