Alarge plate is fabricated from a steel alloy that has a plane strain fracture toughness of 78 mpa (70.98 ksi). if the plate is exposed to a tensile stress of 345 mpa (50040 psi) during use, determine the minimum length of a surface crack that will lead to fracture. assume a value of 1.04 for y.

minimum length of a surface crack is 15.043 mm

Explanation:

given data

strain fracture toughness K = 78 MPa

tensile stress = 345 MPa

Y = 1.04

to find out

minimum length of a surface crack

solution

we find here length of critical interior flaw from formula that is

α  =       ....................1

put here value we get

α  =  

α  = 15.043 mm

so minimum length of a surface crack is 15.043 mm

answer:

d. attempt to find the owner, then leave your information if you cannot find them.

explanation:

d. represents both (b) and (c).

more logical as well.

b and c are to complicated.

glad i could , give me a follow, so if you need with any other question, im here.

answer:

dsfdssdfdssfdsfd

explanation: