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Engineering, 25.10.2019 04:43 aurorasweetpea610
2.19 for a k+βclβ ion pair, attractive and repulsive energies ea and er, respectively, depend on the distance between the ions r, according to e a = β 1.436 r e r = 5.86 Γ 10 β 6 r 9 ea=β1.436rer=5.86Γ10β6r9 for these expressions, energies are expressed in electron volts per k+βclβ pair, and r is the distance in nanometers. the net energy en is just the sum of the preceding two expressions. (a) superimpose on a single plot en, er, and ea versus r up to 1.0 nm. (b) on the basis of this plot, determine (i) the equilibrium spacing r0 between the k+ and clβ ions, and (ii) the magnitude of the bonding energy e0 between the two ions.
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2.19 for a k+βclβ ion pair, attractive and repulsive energies ea and er, respectively, depend on the...
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