Fig. 1 shows an op amp with a negative feedback path.
assume that μ = 800v/v, rs = 20kω, rid = 1000kω,
ro = 10kω, rl = 2kω, r1 = 2kω and r2 = 1kω.
(a) show the expression and calculate the value of
loop gain by breaking the loop at xx’. you must draw
the circuits after breaking the loop. (10%)
(b) if μ increases by 15%, what’s the corresponding increase
in the closed-loop gain? (6%)

answer:

› 2-

2. determine the proper pump operating conditions and bit nozzle sizes for - chegg

answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

//main function

int main()

{

  // variable

 int n;

 cout<<"enter a number:";

 // read the input

 cin>>n;

 // find the square root of the absolute value

 float square_root=sqrt(abs(n));

 // print the square_root

 cout<<"square root of "<<n<<" is: "<<square_root<<endl;

  return 0;

}

Explanation:

Read a number from user and assign it to "n".Then find its absolute value with abs() function.Then calculate the square root of the absolute value with sqrt() function.Print the square root of the number.

Output:

enter a number:-17

square root of -17 is: 4.12311

                                                         This is easy

                                                     sinserly Natalie 7 grader (this is not that hard)

answer:

Tell him to give you another opportunaty to send it to him.