Aparticle moves along a straight line with a velocity in millimeters per second given by v = 436 - 15tº wheret is in seconds. calculate the net displacement as and total distance d traveled during the first 6.7 seconds of motion.

2584.52 mm

Explanation:

Given

Velocity is given=436-15t

V is in mm/s

and we know

Integrating both sides we get

x=2584.52 mm

Here distance is equal to displacement because from graph area under the v -t graph gives displacement when we consider sign and distance if we take absolute values

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