Calculate the equilibrium concentration of vacancies per cubic meter in pure aluminium at 600°c. energy of formation for al is 0.76 ev, atomic weight is 2700 kg/m3 and the atomic weight of al is 26.98 g/mol

equilibrium concentration is 2.477 × vacancies/m³

Explanation:

given data

temperature = 600°C = 873 K

Energy of formation Al = 0.76 eV

atomic density = 2700 kg/m3

atomic weight of Al = 26.98 g/mol

to find out

equilibrium concentration of vacancies

solution

we have given atomic weight and density so we will apply formula that is

N =

here ρ is density and Na is avogadro number i.e 6.022 × atoms/mol and N is related to density

so

N =

N = 6.027 × atoms/m³

and

equilibrium concentration of vacancies is express as

n =

here t is temperature given and Q is energy formation and K is 8.62 × eV/atom

so

n =

n = 2.477 × vacancies/m³

so equilibrium concentration is 2.477 × vacancies/m³

answer:

it will water down the soup lol

explanation: