Around steel bar, 0.02 m in diameter and 0.40 m long, is subjected to a tensile force of 33,000 kg. y=e= 2e10 kg/m^2. (modulus).calculate the elongation in meters.

The elongation in the bar equals 2.1 millimeters.

Explanation:

We know from Hooke's Law

Where

is stress in the material

is strain in the material

'E' is the young's modulus of the material

Now we know that

Applying values we get

Applying the values in the Hooke's relation we obtain

Now by definition of strain we have

answer:

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